Loading... ## 操作列表 ### 遍历列表 ``` dragons = ["Zephy", "Minessa", "Karikaro", "Laponette", "Charlotta", "Faria", "Monet", "Chiquita", "Pio"] for dragon in dragons: #for 遍历,':'不能少 print(f"\t{dragon.title()} is a dragon-witch") print(f"I am happy to see you, {dragon.title()}") #依靠缩进判断关系，忘记缩进或者少缩进，甚至不必要的缩进也是错误，这就与c中的';'一样重要 print("These are the dragons in 'Dragon Star Varnir'") ``` 结果 ``` Zephy is a dragon-witch I am happy to see you, Zephy Minessa is a dragon-witch I am happy to see you, Minessa Karikaro is a dragon-witch I am happy to see you, Karikaro Laponette is a dragon-witch I am happy to see you, Laponette Charlotta is a dragon-witch I am happy to see you, Charlotta Faria is a dragon-witch I am happy to see you, Faria Monet is a dragon-witch I am happy to see you, Monet Chiquita is a dragon-witch I am happy to see you, Chiquita Pio is a dragon-witch I am happy to see you, Pio These are the dragons in 'Dragon Star Varnir' ``` ### 数值列表 ``` for value in range(1, 5): print(value)##差一行为，1-5代表1，2，3，4 even_numbers = list(range(2, 12, 2))##list可以将range()转化为一胜一负列表 print(even_numbers)##可以看到差一行为导致没有12 ## 创建特定数组的办法，比如1-10的平方 squares = [] for value in range (1, 11): square = value ** 2 squares.append(square) print(squares) ## 简单计算 print(f"min: {min(squares)} max: {max(squares)} sum: {sum(squares)}") ## 列表解析 cubic = [value**3 for value in range(1, 11)] ## 指定的列表名 = [表达式 for循环提供值给列表式] print(cubic) test = [sum(squares)/sum(cubic) for value in range(1, 11)] print(test) test = [sum(squares)/value for value in cubic] print(test) ``` 结果 ``` 1 2 3 4 [2, 4, 6, 8, 10] [1, 4, 9, 16, 25, 36, 49, 64, 81, 100] min: 1 max: 100 sum: 385 [1, 8, 27, 64, 125, 216, 343, 512, 729, 1000] [0.12727272727272726, 0.12727272727272726, 0.12727272727272726, 0.12727272727272726, 0.12727272727272726, 0.12727272727272726, 0.12727272727272726, 0.12727272727272726, 0.12727272727272726, 0.12727272727272726] [385.0, 48.125, 14.25925925925926, 6.015625, 3.08, 1.7824074074074074, 1.1224489795918366, 0.751953125, 0.5281207133058985, 0.385] ``` ### 使用列表的一部分 ``` dragons = ["Zephy", "Minessa", "Karikaro", "Laponette", "Charlotta", "Faria", "Monet", "Chiquita", "Pio"] print(dragons[0:3]) print(dragons[1:4])##差一行为 print(dragons[:4]) print(dragons[5:]) print(dragons[-3:]) for dragon in dragons[1:4]: print(f"I love {dragon}. だいすき(daisuki)") print(f"别看了太艹了")#记得缩进问题 list = dragons[:] print(list.pop()) print(f"list\t{list}") print(f"dragons\t{dragons}") ##使用List = dragons 则是关联而不是复制 list_2 = list list.append("Cosettia") print(f"list:\t{list}") print(f"list_2:\t{list_2}") ``` 结果 ``` ['Zephy', 'Minessa', 'Karikaro'] ['Minessa', 'Karikaro', 'Laponette'] ['Zephy', 'Minessa', 'Karikaro', 'Laponette'] ['Faria', 'Monet', 'Chiquita', 'Pio'] ['Monet', 'Chiquita', 'Pio'] I love Minessa. だいすき(daisuki) I love Karikaro. だいすき(daisuki) I love Laponette. だいすき(daisuki) 别看了太艹了 Pio list ['Zephy', 'Minessa', 'Karikaro', 'Laponette', 'Charlotta', 'Faria', 'Monet', 'Chiquita'] dragons ['Zephy', 'Minessa', 'Karikaro', 'Laponette', 'Charlotta', 'Faria', 'Monet', 'Chiquita', 'Pio'] list: ['Zephy', 'Minessa', 'Karikaro', 'Laponette', 'Charlotta', 'Faria', 'Monet', 'Chiquita', 'Cosettia'] list_2: ['Zephy', 'Minessa', 'Karikaro', 'Laponette', 'Charlotta', 'Faria', 'Monet', 'Chiquita', 'Cosettia'] ``` ### 元组 ``` menu = ("a", "b", "c", "d", "e") for dish in menu: print(f"we provide {dish}.") menu = ("c", "d", "e", "f", "g") for dish in menu:##元组是不能赋值的，但可以重新定义 print(f"we provide {dish} today.") ``` 结果 ``` we provide a. we provide b. we provide c. we provide d. we provide e. we provide c today. we provide d today. we provide e today. we provide f today. we provide g today. ``` ### 代码格式 PEP 8 Last modification：February 14, 2022 © Allow specification reprint Like 如果觉得我的文章对你有用，请留下评论。